He proof TriangleABC ≅ TriangleDCB that is shown.

Given: AngleA ≅ AngleD; CD||AB
Prove: TriangleABC ≅ TriangleDCB

Triangles C D B and C A B are shown. Angles C D B and C A B are congruent. Sides D C and A B are parallel.
What is the missing reason in the proof?

A 2-column table has 5 rows. Column 1 is labeled Statement with entries angle A is-congruent-to angle D, line segment C D is parallel to line segment A B, line segment C B is-congruent-to line segment B C, angle A B C is-congruent-to angle D C B, triangle A B C is-congruent-to triangle D C B. Column 2 is labeled Reason with entries given, given, reflective property, alternating interior angles are congruent, question mark.

alt. ext. Angles are ≅
ASA
AAS
corr. int. Angles are ≅

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

answer: i believe the answer is e

step-by-step explanation: