A die is rolled twice. What is the probability of showing a 1 on the first roll and an even number on the second roll?
Durian

1/12

Step-by-step explanation:

Okay, so this will be a compound probability question because there are two parts to the question.

Firstly, a die has 6 sides, and there is only one chance of getting a 1, so the probability would be 1/6.

Furthermore, there are 3 different even numbers on a 6-sided die, so that is 3/6, which can be simplified to 1/2.

Now, because this is a compound probability, we have to multiply 1/2 and 1/6 together, which would give us our answer of 1/12.

1/12

Step-by-step explanation:

The sample space when a die is rolled twice is given below:

123456

11,11,21,31,41,51,6

22,12,22,32,42,52,6

33,13,23,33,43,53,6

44,14,24,34,44,54,6

55,1,5,25,35,45,55,6

66,15,26,36,46,56,6

Those showing a one on the first throw and an even number on the second roll are:

{ 1,2 : 1,4 : 1,6}

Therefore :

the probability of showing a 1 on the first roll and an even number on the second roll = 3/36

= 1/12

21/58.

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