The sum of two numbers is 35. Their difference is 3. Find the numbers

19 and 16

Step-by-step explanation:

Let x and y be the two numbers

x+y = 35

x-y =3

Add the two equations together

x+y = 35

x-y =3

2x = 38

Divide by 2

2x/2 = 38/2

x = 19

Solve for y

x-y = 3

19-y = 3

Subtract 19 from each side

19-19 -y = 3-19

-y = -16

y =16

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!