The common difference, d, in an arithmetic sequence whose fourth
term is 16 and whose seventh term is 31.

5

Step-by-step explanation:

Arimethic progression

An=a1+(n-1)d

An= nth term

A1= first term

N= nth position

D= common difference

For the 4th term=16

A4=a1+(n-1)d

16=a1+(4-1)d

16=a1+3dequation 1

For the 7th term=31

A7=a1+(n-1)d

31=a1+(7-1)d

31=a1+6dequation 2

Subtract equation 1 from 2

31=a1+6d

16=a1+3d

15=3d

D=15/3

D=5

Common difference is 5

the factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. hope this ! mark brainliest! you v much! : )