Graph a line with a slope of -\dfrac34−
4
3

minus, start fraction, 3, divided by, 4, end fraction that contains the point (2,3)(2,3)left parenthesis, 2, comma, 3, right parenthesis.

Given:

It is given that the slope and contains the point (2,3)

We need to determine the graph of the line.

Equation of the line:

The equation of the line can be determined using the formula,

Substituting the point (2,3) and the slope in the above formula, we get;

Thus, the equation of the line is

Graphing the line:

The equation of the line can be graphed by plotting the x and y intercepts.

The x - intercept is the value of x when y = 0. Thus, we get;

Thus, the x - intercept is (6,0)

The y - intercept is the value of y when x = 0. Thus, we get;

Thus, the y - intercept is (0,4.5)

Hence, plotting these points and joining the line, we get the graph of the line

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i