Mr. Williams is building a sand box for his children. It cost $228 for the sand if he builds a regular-sandbox with dimensions 9‘ x 6‘. How much will the same cost if he decides to increase the size to 13 1/2‘ x 9‘?

It will cost $512.73

Step-by-step explanation:

9 in by 6 in sandbox cost $228

i.e., 9*6 = 54 in²

54 in² cost $228

1 in² will cost $228/54

≈ $4.22

If the new dimension is 13 1/2 in by 9 in

then area will be 13 1/2*9

27*9/2 = 121.5 in²

The cost of 121.5 in² will be

121.5*4.22 = $512.73

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step-by-step explanation:

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere