A particle P of weight 20 N is suspended by two strings AP and BP. The tension in string AP is (ai+8j)
and the tension in string BP is (6i+bj)
The value of a is?
And the value of b is?

The magnitude of the tension in string AP is?

The angle that string BP makes with the vertical is?

Give your answers as exact whole numbers or as decimals to 3 s. f.

the answer is b. 60. each interior angle in 120, so the exterior angle must be 60 in order to add up to 180

step-by-step explanation:

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

hope this !

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

the answer is d

step-by-step explanation:

you can also use mathway to get you answer + steps