How do I solve this equation using the substitution method? They want me to isolate x in the first equation.
x + 3y = -5
4x - y = -33

Step-by-step explanation:

X+3y= -5

4x-y= -33

1. X=-3y-5 (move the variable to the other side of the equation)

2. 4(-3y-5)-y= -33 (substitute the value of x)

3. -12y-20-y= -33 (cross multiply)

4. -13y-20= -33 (reduce)

5. -13y= -33+20 (isolate variable)

6. -13y= 13 (addition or subtraction)

7. Y= 13÷(-13) (divide)

8. Y= -1

9. X+3(-1)= -5 (substitute value into other equation)

10. X-3= -5 (multiply)

11. X= -5+3 (move to the other side)

12. X= -2 Y= -1

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)