The population of a town is increasing at a rate of 2.8% per year. In 2001 the town had a population of 34,229. Find the population of the town in 2013

The population of the town in 2013 is 47,677. (to the nearest whole number)

Step-by-step explanation:

To calculate this, we will compare the increase to the increase of the present value of an amount of money invested in 2001, increasing at an annual percentage rate of 2.8%, to yield the future value worth a certain amount in 2013. To calculate, the formula below is used:

FV =

where:

FV = Future Value = ???

PV = present value = 34,229

i = interest in decimal = 2.8% = 0.028

n = frequency of compounding period per year = 1

t = number of compounding years = 2001 to 2013 = 12 years.

FV =

FV = 34,229 × (1.028)¹²

FV = 47,677.29 = 47,677 (to the nearest whole number)

correct answer:

i^31 = -i

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

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