A rotating light is located 20 feet from a wall. The light completes one rotation every 3 seconds. Find the rate at which the light projected onto the wall is moving along the wall when the light's angle is 10 degrees from perpendicular to the wall.

43.17 ft/s

Step-by-step explanation:

Let the height of the wall is y.

distance of wall from light is 20 feet.

y = 20 tanθ    .... (1)

time period, T = 3 second

Differentiate equation (1) with respect to t.

dy/dt = 20 x 2.16

dy/dt = 43.17 ft/s

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

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step-by-step explanation: