Mathematics, 04.04.2020 11:08 sumansmith5288

Hence solve for x and y the simultaneous equations: log2x + 2log4y =4
log10( x + y ) =1

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Hence solve for x and y the simultaneous equations: log2x + 2log4y =4
log10( x + y ) =1...

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Hence solve for x and y the simultaneous equations: log2x + 2log4y =4 log10( x + y ) =1

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Another question on Mathematics

Hence solve for x and y the simultaneous equations: log2x + 2log4y =4
log10( x + y ) =1