The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4. This distribution takes only whole-number values, so it is certainly not a normal distribution. Let "x-bar" be the mean number of accidents per week at the intersection during a year (52 weeks). What is the approximate probability that there are fewer than 100 accidents in a year? (Hint: Restate this event in terms of "x-bar")

The approximate probability that there are fewer than 100 accidents in a year = .9251

Step-by-step explanation:

Given -

Mean =2.2

Standard deviation = 1.4

Let  be the mean number of accidents per week at the intersection during a year (52 weeks)

Then = = 1.92

the approximate probability that there are fewer than 1.92 accidents per week  in a year

[Z   = ]

=    = (

 = P( )   ( Using Z table)

=  .9251

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length