In a thunderstorm, the wind velocity in meters per second can be described by the function v(p) = 5.7 √998 - p, where p is the air pressure in millibars. What is the air pressure of a thunderstorm in which the wind velocity is 49.3 meters per second?

923.1927 millibars

Step-by-step explanation:

The wind velocity is given by the function:

#We make p the subject of the formula:

#Substitute the given values in the function above to solve for p;

Hence, the air pressure is 923.1927 millibars.

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step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.