Crude oil is leaking from a tank at the rate of 10% of the tank volume every 3 hrs. If the tanker originally contained 500,000 gallons of oil, how many gallons of oil remain in the tank after 4 hrs? Round to the nearest gallon.

  434,470 gallons

Step-by-step explanation:

The exponential equation for the volume v remaining after t hours can be written as ...

  v(t) = (initial amount)×(decay factor)^(t/(decay time))

  v(t) = 500,000×(1 -10%)^(t/3)

Then after 4 hours, the remaining volume is ...

  v(4) = 500,000×(0.90^(4/3)) ≈ 434,470 . . . . gallons

Comment on the form of the equation

The decay factor is related to the decay rate by ...

  decay factor = 1 - (decay rate)

and the decay time is the time applicable to that decay rate. Here, the rate is 10% every 3 hours, so the decay time is 3 hours for a decay rate of 10%.

true? is that what you're asking or do you mean something else?

sorry not sure

step-by-step explanation: