Consider triangle ABC and triangle ACD in the diagram below. Which of the following complete the proof above?
Options
- AB =AD
- AC=AC
- AC=BD
- BC=DC

Given:

AC is perpendicular bisector of BD

AB ≅ AD

To prove:

ΔABC ≅ ΔACD

Solution:

In triangle ABC and triangle ACD,

Step 1: Given

AC is perpendicular bisector of BD and

AB ≅ AD (Side)

Step 2: By perpendicular bisector definition,

BC ≅ CD (Side)

Step 3: By reflexive property,

AC ≅ AC (Side)

Step 4: By SSS congruence criterion,

ΔABC ≅ ΔACD

Hence proved.

add an image, and i will answer

step-by-step explanation:

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9