An accepted relationship between stopping distance, d in feet, and the speed of a car, v in mph, is d(v) = 1.2 v + 0.04 v^2 on dry, level concrete. (a) How many feet will it take a car traveling 40 mph to stop on dry, level concrete? (b) If an accident occurs 200 feet ahead, what is the maximum speed at which one can travel to avoid being involved in the accident?

123453245

Step-by-step explanation:

21435646gmj

answer: the equation matches the regression

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)