If f(1)=9 and f(n)=f(n-1)+2 then find the value of f(5)

Step-by-step explanation:

hello :

f(n)=f(n-1)+2

means : f(n)-f(n-1)=2

this is the arithmetic seq when the common dif is d= 2  and the first term is : 9

the n-ieme term is : f(n)  = f(1) +(n-1)d

f(n) =9+2(n-1)

f(n) = 2n+7

so : f(5) = 2(5)+7 = 17

umumumumum

im not sure

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.