Mathematics, 03.04.2020 04:41 nestergurl101
\begin{aligned} &f(t)=\dfrac{2t+7}{t-3} &h(n)=-2n^2-3n+1 \end{aligned} f(t)= t−3 2t+7 h(n)=−2n 2 −3n+1 f(h(-1))=f(h(−1))=
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\begin{aligned} &f(t)=\dfrac{2t+7}{t-3} &h(n)=-2n^2-3n+1 \end{aligned} f(t)= t−3 2t+7 h(n...
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