Eleven letters spelling "probability" are placed in a bag. You pick one, replace it, and then pick another. What is the probability of picking a P and then a I?

It is 2/121.

Step-by-step explanation:

For the first draw, the probability of picking P is 1/11 since there is only one P letter in the 11 letters. If we replace the P after drawing, then for the second draw, the probability of drawing I is 2/11 since there are 2 I's in the 11 letters.

Since the events are seperate, the probability of picking P and then picking I is (1/11)x(2/11) = 2/121.

I hope this answer helps.

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation:

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.