The congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle. The perimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle. What is the length of the shortest side of the triangle?

units

ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga ooga booga

step-by-step explanation:

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb