If AH = 8 mm, A F = 17 mm, and FC = 41 mm, what would be the distance between A and D? Round your answers to two decimal places. (had to put a bunch of spaces between a and f cuz wouldnt allow it lol

AD = 27.29

Step-by-step explanation:

Notice that you can use similar triangles to solve this problem.

The small triangle on the top right (AFH) is similar to the triangle ACD.

So you can use that the ratio between corresponding sides must be equal.

Notice also that the side AC has length = 17 mm + 41 mm = 58 mm

You can set then the following proportion:

in decimal form, this can be rounded to: 27.29

19.29 mm

Step-by-step explanation:

AH/AD = A F/AC

8/AD = 17/(41+17)

AD = 8 × 58/17

AD = 27.2941176472

HD = AD - AH

= 27.2941176472 - 8

= 19.2941176471

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step-by-step explanation:

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.