What is the maximum number of possible solutions for the system shown
below?

х2 – 4у2 = 16
x2+y2 = 36

А. 2
B. 4
C. 3
D. 1

4

Step-by-step explanation:

х^2 – 4у^2 = 16 is the equation of a hyperbola with center at the origin.  Parts of this graph show up in all four quadrants.

Similarly, x^2 + y^2 = 36 is the equation of a circle with center at the origin); the graph shows up in all four quadrants.

So there is an intersection of the graphs in all four quadrants.  Therefore, 4 is the maximum number of possible solutions of the system shown.

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

what level of math? also i don't need to be paid if i can you.