Find the 74th term of the arithmetic sequence of 19,26,33

530

Step-by-step explanation:

19,26,33

For this A. P

first term (a)  = 19

Common difference (d) = 2nd term - 1st term =

=  3rd term - 2nd term

d = 26 -19 = 33 - 26

d = 7

Nth term of an AP (Tn) = a + (n - 1)d

Where n = number of term

For T 74

n = 74

Therefore

T 74 = a + (n - 1)d

T 74  = 19 + (74 - 1) × 7

T 74 = 19 + 73 × 7

T 74 = 19 + 511

T 74 = 530

Therefore the 74th term = 530

hope this was helpful, please rate as brainliest

yes yes yes yes yes yes yes yes yes

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2