PLZZ IM CRYING HEL
At a fair, each person can spin two wheels of chance. The first wheel has the numbers 1 and 4. The second
wheel has the letters M, A, T, H.
List all the possible outcomes of the
compound event.
What is the probability of spinning a 1 on
the first wheel?
What is the probability of spinning a T on
the second wheel?
If you spin both wheels, what is the
probability that you get either a 1 or a T?
If you spin both wheels, what is the
probability of getting a 1 and a T?

possible outcomes

1a

1b

2a

2b

3a

3b

there are a total of 2 number one's

so there is a possibility of 2/6 chance to get the number 1

There are 3 a's in the set of data so there is a 3/6 chance to get an a

But we should exclude 1a because it is already counted in the first set when we counted the total number of 1's so there is a 2/6 chance of getting an A

add

2/6+2/6=4/6

There is a 4/6 or 2/3 chance of getting either an a or an 1

Step-by-step explanation:

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

529 and 531

step-by-step explanation: