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Mathematics, 03.04.2020 00:07 maleah12x

\frac{x^2+9x+18}{x^2+6x+8}\div \frac{x^2βˆ’3xβˆ’18}{x^2+2xβˆ’8}=

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\frac{x^2+9x+18}{x^2+6x+8}\div \frac{x^2βˆ’3xβˆ’18}{x^2+2xβˆ’8}=...
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