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Mathematics, 02.04.2020 21:34 Sumitco9578

Multiply

7k3(4k2βˆ’3)

Question 4 options:

28k5βˆ’21k3

11k5+4k3

8kβˆ’4

28k6βˆ’21k3

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Answers: 3

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Multiply

7k3(4k2βˆ’3)

Question 4 options:

28k5βˆ’21k3

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