Please Help Soon. Urgent!!

A cylindrical vase has a diameter of 6 in. At the volume of the vase, there are 9 marbles, each of diameter 3 inches. The base is filled with water up to a height of 12in. Which of the following could be used to calculate the volume of the water in the vase?

π(3in)^2(12in) - 1.5(4/3 π(9in)^3)
π(12in)^2(3in) - 1.5(4/3 π(9in)^3)
π(3in)^2(12in) - 9(4/3 π(1.5in)^3)
π(12in)^2(3in) - 9(4/3 π(1.5in)^3)

It's the third choice:

π(3in)^2(12in) - 9(4/3 π(1.5in)^3).

Step-by-step explanation:

The volume of the water + the 9 marbles

= π r^2 h

= π * 3^2 * 12. in^3.

Volume of the 9 marbles

= 9 * 4/3  π r^3

= 9 * π  * 4/3 * 1.5^3

So the volume of the water

= π(3in)^2(12in) - 9(4/3 π(1.5in)^3).

uhhh idk u yolo?

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft