Determine the discriminant for the quadratic equation 0 = –2x2 + 3. based on the discriminant value, how many real number solutions does the equation have?

discriminant = b2 – 4ac

real number solutions

If you would like to know the discriminant of the quadratic equation 0 = -2x^2 + 3, you can do this using the following steps:

0 = -2x^2 + 3

0 = ax^2 + bx + c
a = -2, b = 0, c = 3

D = b^2 - 4 * a * c = 0^2 - 4 * (-2) * 3 = 0 + 4 * 2 * 3 = 24

The discriminant is 24 (positive).

If the discriminant of a quadratic equation is equal to zero (b^2 - 4ac = 0), there is one real root which is repeated. If the discriminant is positive (b^2 - 4ac > 0), there are two real roots; and if the discriminant is negative (b^2 - 4ac < 0), there are two complex roots.

Therefore, the equation has 2 real number solutions.

two

Step-by-step explanation:

It has two real number solutions I just know because I got this question right on my test. FYI Im not that good in algebra

answer set (b) 0.5, 3/4 80% is in order from least to greatest.  

step-by-step explanation:

in order to compare rational numbers to each other, it is much easier if they are in the same form.   typically, the best form in which to evaluate rational numbers is in decimals.   in order to convert a percent to a decimal, you would divide the given percentage by 100.   you can also accomplish the conversion by moving the decimal point over two places to the left.   for example, the decimal value of 80% is 80/100, or 0.8.   in order to convert a fraction to a decimal, you need to divide the numerator by the denominator.   for example, 3/4 is 0.75.   so, for choice (b) 0.5 3/4 (0.75), 80% (0.8) is the only choice in which the numbers are in order from least to greatest.