Solve the system of equations 2x 3y = 40 and –2x 2y = 20. a. x = –6, y = 4 b. x = 10, y = 20 c. x = –10, y = 20 d. x = 2, y = 12

If you would like to solve the system of equations, you can do this using the following steps:

2x + 3y = 40
-2x + 2y = 20

2x + 3y - 2x + 2y = 40 + 20
5y = 60   /5
y = 60/5
y = 12

2x + 3y = 40
2x + 3 * 12 = 40
2x + 36 = 40
2x = 40 - 36
2x = 4
x = 4/2
x = 2

(x, y) = (2, 12)

The correct result would be d. x = 2, y = 12.