) If the gradient of ff is ∇f=xi⃗ +yj⃗ +3zyk⃗ ∇f=xi→+yj→+3zyk→ and the point P=(−6,−6,−2)P=(−6,−6,−2) lies on the level surface f(x, y,z)=0f(x, y,z)=0, find an equation for the tangent plane to the surface at the point PP.

-3x-3y-z=38

Step-by-step explanation:

To find the equation of the tangent plane you can use

the point P is (-6,-6,-2). Hence you have

hope this helps!!

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

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step-by-step explanation: