Triangle ABC with vertices A(−2, −4), B(1, −3), and C(3, 3) is translated by (x, y) arrowright (x − 7, y + 7). Then the image, triangle A′B′C′, is translated by (x, y) arrowright (x + 8, y − 6), resulting in A″B″C″.

Find the coordinates for the vertices of triangle A″B″C″.

The coordinates are A″(
,
), B″(
,
), and C″(
,
).

Enter a rule for one translation that maps triangle ABC to triangle A″B″C″.

A single rule that maps triangle ABC to triangle A″B″C″ is (x, y) arrowright (x +
, y +
).

the answer is 31.27mph

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).