A golf ball is hit from a hill, and its height can be modeled by h(t)= -16 + 32t + 48, where he is the
height in feet and is the time in seconds. How long will it take for the ball to reach 64 feet.

  1 second

Step-by-step explanation:

We assume your model is intended to be ...

  h(t) = -16t^2 +32t +48

Setting this equal to 64, we can find t ...

  64 = -16t^2 +32t +48

  t^2 -2t +1 = 0 . . . . . . subtract 64 and divide by -16

  (t -1)^2 = 0 . . . . . . . . factor the square

  t = 1 . . . . . . . . . . . . . the only solution

It will take the ball 1 second to reach a height of 64 feet.

the awnser is visionary