A circular target is divided into four rings that have equal areas. If the radius of the target is 24cm, find the radius of the circle at the centre of the target.

THE AREA OF THE RING WHICH IS INSIDE CIRCULAR TARGET IS 12CM.

Step-by-step explanation:

A circular target which is divided into four rings of equal areas as given in the information

The area of the circular target is

Area = * R².

As per the given data radius of the target 'R' is 24cm,

Area of circular target = * 24²

=>  576 .

let us consider radius of ring equals to 'r',

So, each of the ring has area of

=> Area of ring = ( * 576) / 4

=> 144 *

Now let us consider area of the small ring inside circular target

Area of ring = * r²

* r² = 144  

Taking off the from both sides

r² = 144

r = 12.

Therefore radius of ring which is inside circular target is 12 cm.

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.