Mathematics, 01.04.2020 22:31 chasadyyy

Nina bicycles 4 miles west to get from her house to school. After school, she bicycles 3 miles north to her friend Tracy's house. How far is ninas house from Tracy's house, measured in a straight line

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Answer from: zack66828

Distance between nina's house to her friend's home = AC = 5 miles

Step-by-step explanation:

Distance between nina's house to her school = BC = 4 miles

Distance between nina's school to her friend's home = BA = 3 miles

Distance between nina's house to her friend's home = AC = ??

From the ΔABC

$AC^{2} = AB^{2} + BC^{2}$

$AC^{2} = 3^{2} + 4^{2}$

$AC^{2} =25$

AC = 5 miles

Therefore Distance between nina's house to her friend's home = AC = 5 miles

Nina bicycles 4 miles west to get from her house to school. After school, she bicycles 3 miles north

Answer from: Quest

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

$\tan\left(x\right)=\frac{\left[altitude\right]}{\left[base\right]}=\frac{p}{r}$

$\tan\left(x\right)=\frac{p}{r}$

$\frac{p}{r}=tan(x)$

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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