7 times a number is 8 less than the square of that number. Find the negative solution

x=-1

Step-by-step explanation:

Let x = the number

7x =x^2 -8

Subtract 7x from each side

7x-7x = x^2 -7x -8

0 = x^2 -7x -8

Factor

0 = (x-8) (x+1)

Using the zero product property

x-8 =0     x+1 =0

x=8           x=-1

We want the negative solution x=-1

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right