What is the value of x in the equation ln (x + 6) – ln (2x – 1) = 1?

1.95

Step-by-step explanation:

hello :

ln (x + 6) – ln (2x – 1) = 1  ...(*)

this expression exist : 2x-1 > 0 and x+6 > 0   means : x> 1/2 and x  > -6

hence for : x> 1/2   (*) equivalent to  ln((x+6)/(2x-1))= lne(1=lne)

(x+6)/(2x-1) = e

x+6 = e(2x-1)        means : x+6 = 2ex-e

-x+2ex = e+6

x(2e-1) = e+6

x = (e+6)/(2e-1)    =(2.73+6)/(2(2.73)-1) =8.73/4.46 =1.95

ddsf

step-by-step explanation:

dfs

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)