2/5(d-10)-2/3(d+6) is...

Let's simplify step-by-step.

2/5(d−10)− 2/3(d+6)

Distribute:

=(2/5)(d)+(2/5)(−10)+ −2/3d+−4

=2/5d+−4+ −2/3d+−4

Combine Like Terms:

=2/5d+−4+ −2/3d+−4

=(2/5d+ −2/3d)+(−4+−4)

=−4/15d+ −8

−4/15d+ −8

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answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

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