What happens to the value of the expression 100 - x100−x100, minus, x as xxx increases?

with increasing the value of x , value of expression decreases continuously .

Step-by-step explanation:

Here we have , an expression as 100-x or , . We need to tell what happens to the value of expression when value of x increases :

According to question ,Given expression is in form of f(x) = mx +c ,value of slope & y-intercept is :

Now , from the graph attached we can see that

For x<100 :

For x=100 :

For x>100 :

Hence , with increasing the value of x , value of expression decreases continuously .

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752