A standard deck of 52 cards contains 4 suits: hearts, clubs, diamonds, and spades. Each suit consists of cards numbered 2 through 10, a jack, a queen, a king, and an ace.

Bashir decides to pick one card at random from a standard deck of 52 cards. Let F be the event that he chooses a face card(a jack, queen, or king of any suit) and S be the event that he chooses a spade.

what is P (F or S), the probability that the card Bashir chooses is either a face card or a spade?

Step-by-step explanation:

The total number of cards, n (C) = 52

Let F be the event that he chooses a face card(a jack, queen, or king of any suit)

The total number of cards in F event, n (F) = 3 * 4 (no of suits) = 12

S be the event that he chooses a spade,

The total number of cards in S event, n (S) = 13

n (A ∩ B) = 3

The probability that the card Bashir chooses is either a face card or a spade,

P (F or S) = [ n(F) + n(S) - n(F ∩ S) ] / n (C)

= [ 13 + 12 - 3 ] / 52

= 22 / 52 = 11 / 26

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb

answer: 24

step-by-step explanation: you have to make a list of each of the orders