Find the value of x to the nearest tenth.
9.0
8.6
26.3
5.7

x = 9.0

Step-by-step explanation:

From the given right angle triangle,

the hypotenuse of the right angle triangle is x

With m∠39 as the reference angle,

the adjacent side of the right angle triangle is 7

The unknown side represents the opposite side of the right angle triangle.

To determine x, we would apply

the cosine trigonometric ratio which is expressed as

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 39 = 7/x

x = 7/cos 39 = 7/0.777

x = 9.0 to the nearest tenth

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

d

step-by-step explanation:

i used the pitagoras theoreme