Which is a quadratic function having a leading coefficient of 3 and a constant term of -12?
. f(x) =-12x2 + 3x + 1
f(x) = 3x2 + 11x-12
f(x) = 12x2 + 3x + 3
f(x) = 3x - 12

256π units²   (answer b)

step-by-step explanation:

the formula for the surface area of a sphere of radius r

is             a = 4πr²

and so, if r = 8 units, then the surface area is:

a = 4π(8 units)² = 256π units²   (answer b)

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

is there a question here?

step-by-step explanation:

ιт 45,000 мєтєяѕ тσ ℓαѕ νєgαѕ

нσρє ι ¢συℓ∂ нєℓρ