A circular path 2 feet wide has an inner diameter of 950 feet. How much farther is it around the outer
edge of the path than around the inner edge? Round to nearest hundredth. Use 3.14 for it.
The outer edge of the path is
feet farther around than the inner edge.

12.56 feet

Step-by-step explanation:

Given: The width of the circular path= 2 feet

The inner diameter of circular path= 150 feet

Therefore, the inner radius of circular path=

Now, the outer radius= 75+2=77 feet

We know that the circumference=

Inner circumference=

Outer circumference=

The difference=

Hence, the outer edge of the path is 12.56 feet farther than the inner edge

step-by-step explanation:

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$15

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when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation: