You must roll a total of 9 on two number cubes to win the game. Alex must roll a 6. Who is more likely to win the game on the next turn? Explain.

Alex has a higher probability than the other player.

Step-by-step explanation:

When 2 die are used there are 36 possibilities outcomes of averaged low to high numbers using each number fairly as unit on combined 12 sides.

We know this as a cube has 6 sides and that there are 2 x dice   each showing the equivalent of;

(1, 2, 3, 4, 5, 6 ) x 2

For Alex equaling 6 he has 5/36  probability of rolling 6

4 + 2   5+ 1   1+ 5   2+4  + 3+3  

= 5/36 probability of rolling 6 as we count up.

To find 2 die equaling 9 we have 4/36 we know it's less as numbers 3, 3 makes 6 and stands out.

We show are workings,

Find 9

6+ 3 = 9

5 +4  = 9

Just like;

3+ 6 = 9

4+ 5 =9

= 4 rolls = 4/36 probability of rolling a 9.

i dont know and i dont care for math bc it is a stupied subject

step-by-step explanation:

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: