Trig please help

Law of Sines and the Ambiguous Case.

In ∆ ABC, a =13, c = 12, and m < A = 55*
How many distinct triangles can be drawn given these measurements?

One

Step-by-step explanation:

13/sin(55) = 12/sinC

sinC = 0.7561403486

C = 49.1, 130.9

Since 130.9+55 = 185.9 > 180

It will not form a triangle

So only one triangle possible with angle 49.1° at C

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

if the probability is 1/12, 75 people will receive a $25 gift card

step-by-step explanation: