Use a(t) = −9.8 meters per second per second as the acceleration due to gravity. (Neglect air resistance.) A canyon is 2100 meters deep at its deepest point. A rock is dropped from the rim above this point. How long will it take the rock to hit the canyon floor? (Round your answer to one decimal place.)

Step-by-step explanation:

Given that rock experiments a constant acceleration, position function can be obtained by integrating twice:

The initial conditions of the rock are, respectively:

Position of the rock as a function of time is:

The time taken for the rock to hit the canyon floor is:

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.