Suppose we take two different random samples from the same population of test scores. The population mean and standard deviation are unknown. The first sample has 25 data values. The second sample has 64 data values. Then we construct a 95% confidence interval for each sample to estimate the population mean. Which confidence interval will have greater precision (smaller width) for estimating the population mean?

The 95% confidence interval obtained with a sample size of 64 will give greater precision.            

Step-by-step explanation:

We are given the following in the question:

A 95% confidence interval is calculated with the following sample sizes

The population mean and standard deviation are unknown.

Effect of sample size on confidence interval:

If we want a confidence interval with greater precision that is smaller width, we have to choose the higher sample size.

Thus, the 95% confidence interval obtained with a sample size of 64 will give greater precision.

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)