Car A and Car B both start from the same position. Car A travels north at 30mph and Car B travels west at 20mph. Find the rate at which the distance between the two cars is changing at time t = 2 hours.

  about 36.1 miles per hour

Step-by-step explanation:

The cars' distance from the starting point is proportional to time, since both started at the same time. 1 hour after they started, Car A is 30 miles north of the origin, and Car B is 20 miles west of the origin. The distance between them can be found using the Pythagorean theorem:

  d = √(30² +20²) = √(900 +400) = 10√13 ≈ 36.056

The distance between the cars is increasing at the constant rate of about 36.1 miles per hour.

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it