Question 4 options: Find the mean and standard deviation for a binomial distribution with 680 trials and a probability of success of 0.55 and enter the answers below. Round the mean to the nearest integer and the standard deviation to two decimal places.

Mean for a binomial distribution = 374

Standard deviation for a binomial distribution = 12.97

Step-by-step explanation:

We are given a binomial distribution with 680 trials and a probability of success of 0.55.

The above situation can be represented through Binomial distribution;

where, n = number of trials (samples) taken = 680 trials

            r = number of success  

           p = probability of success which in our question is 0.55

So, it means X ~

Now, we have to find the mean and standard deviation of the given binomial distribution.

                    E(X) = n p

       So, E(X) = 680 0.55 = 374

                   S.D.(X) =

                               =

                               = = 12.97

Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.

1 and 0

step-by-step explanation: