A radioactive substance decays according to the following function, where yo is the initial amount present, and y is the amount present at time t (in days). y=y_o e^-0.0645t Find the half-life of this substance. Do not round any intermediate computations, and round your answer to the nearest tenth days

The half-life of the substance is approximately 10.7 days.

The decay of a radioactive isotope is represented by the following exponential model:

(1)

Where:

The half-life of the substance () can be found by this expression:

(2)

If we know that , then the half-life of this substance is:

The half-life of the substance is approximately 10.7 days.

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Therefore 10.75 days is the half life of the given radioactive substance.

Step-by-step explanation:

Given that, a radioactive substance decays function is

where y₀= initial amount of radioactive substance

y= The amount of radioactive substance at time t.

t is in days

Half life is the time required to reduce the amount of the substance to its half of the initial amount.

For half life

Putting the value of y in the given function

Taking ln both sides

    [  ]

      =10.75 days.

Therefore 10.75 days is the half life of the given radioactive substance.

step-by-step explanation:

given expression is .

now we need to simplify the given expression .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

expanding that will give a very very large number so let's keep answer in exponent form.

question 1: step-by-step explanation:

1/4 of 84 = 84÷4= 21