A bowl is designed so that it has a vertical cross-section in the shape of a parabola. The width of the bowl at its opening is 34 centimeters, and the depth of the bowl is 16 centimeters. Assuming that the base of the bowl is represented by the point (0,0), find the equation of a parabola that represents the shape of the bowl

The equation of the parabola is

Step-by-step explanation:

If we have a parabola, we can write that as

As the vertex is in point (0,0), we have that

As the parabola is also symetrical from the y-axis, we have

We result in a equation of the parabola as:

The separation at the opening of the bowl is 34 cm. This opening represents d=2x in the xy-plane.

If the bowl has a depth of 16 cm, we know that at y=16, the value of x should be 34/2=17.

Then we have a point in the parabola that is (x,y)=(17,16).

We can calculate then the paramater a as:

imma say 16%. sorry if its wrong. i'm doing the same stuff right now

step-by-step explanation: